4.9t^2-9.8t=14.7

Solution for 4.9t^2-9.8t=14.7 equation:

4.9t^2-9.8t=14.7

We move all terms to the left:

4.9t^2-9.8t-(14.7)=0

We add all the numbers together, and all the variables

4.9t^2-9.8t-14.7=0

a = 4.9; b = -9.8; c = -14.7;
Δ = b2-4ac
Δ = -9.82-4·4.9·(-14.7)
Δ = 384.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9.8)-\sqrt{384.16}}{2*4.9}=\frac{9.8-\sqrt{384.16}}{9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9.8)+\sqrt{384.16}}{2*4.9}=\frac{9.8+\sqrt{384.16}}{9.8}
$